फ्लोयड के एल्गोरिथम को लागू करने के लिए C प्रोग्राम लिखें ?

#include<stdio.h>
#include<conio.h>
int min(int,int);
void floyds(int p[10][10],int n) {
	int a,b,c;
	for (c=1;c<=n;c++)
	  for (a=1;a<=n;a++)
	   for (b=1;b<=n;b++)
	    if(a==b)
	     p[a][b]=0; else
	     p[a][b]=min(p[a][b],p[a][c]+p[c][b]);
}
int min(int x,int y) {
	if(x<y)
	  return(x); else
	  return(y);
}
void main() {
	int p[10][10],w,n,e,u,v,a,b;
	;
	clrscr();
	printf("\n Enter the number of vertices:");
	scanf("%d",&n);
	printf("\n Enter the number of edges:\n");
	scanf("%d",&e);
	for (a=1;a<=n;a++) {
		for (b=1;b<=n;b++)
		   p[a][b]=999;
	}
	for (a=1;a<=e;a++) {
		printf("\n Enter the end vertices of edge%d with its weight \n",a);
		scanf("%d%d%d",&u,&v,&w);
		p[u][v]=w;
	}
	printf("\n Matrix of input data:\n");
	for (a=1;a<=n;a++) {
		for (b=1;b<=n;b++)
		   printf("%d \t",p[a][b]);
		printf("\n");
	}
	floyds(p,n);
	printf("\n Transitive closure:\n");
	for (a=1;a<=n;a++) {
		for (b=1;b<=n;b++)
		   printf("%d \t",p[a][b]);
		printf("\n");
	}
	printf("\n The shortest paths are:\n");
	for (a=1;a<=n;a++)
	  for (b=1;b<=n;b++) {
		if(i!=b)
		    printf("\n <%d,%d>=%d",a,b,p[a][b]);
	}
	getch();
}