# Sum of Consecutive Cubes Calculator

Calculate the sum of first n cubes or the sum of consecutive cubic numbers from n

n

_{1}^{3 }to n_{2}^{3 }. A cube number (or a cube) is a number you can write as a product of three equal factors of natural numbers. The sum of consecutive cubic numbers from n_{1}^{3 }to n_{2}^{3 }is equal to:n

_{1}^{3 }+ (n_{1}+ 1)^{3}+ ... + n_{2}^{3}### Formula:

Sum of consecutive squares = (n^{2}(n + 1)^{2}/4 )

### Examples

let's understand the simple method to calculate the Sum of consecutive squares for given value as follows:

for example we input the value 5 it means we wants the sum of 1^{3},2^{3},3^{3},4^{3}, and 5^{3}

= 1x1x1 + 2x2x2 + 3x3x3 + 4x4x4 + 5x5x5

= 1 + 8 + 27 + 64 + 125

= 225

now calculate the same example using following formula:

Sum of consecutive squares = (n^{2}(n + 1)^{2}/4 )

= 5x5 (5 + 1)(5 + 1)/4

= 25 (6x6)/4

= 25x36/4

= 25x9

= 225