# Find Volume and Surface Area of Tube Shape Donut

__Surface Area of the Torus :__If we divide the torus into k cylinders each having length l, now consider the division of the torus into k cylinders each having the length l, curved surface area of each such cylinder will be 2

*Π*rl; consequently the surface area of the torus will be 2

*Π*rlk and or we can say the surface area of the torus as 4

*Π*

^{2}rR.

__Volume of the Torus :__If we divide the torus into k cylinders each of length l; then the volume of each cylinder will be

*Π*r

^{2}l. Volume of the torus will be the sum of the volumes of these k cylinders,

*Π*r

^{2}lk. The volume of the torus to be equal to 2

*Π*

^{2}r

^{2}R.

Minor Radius (r) | = |

Major Radius (R) | = |

Tube Shape Donut Surface Area | = ^{2} |

Volume | = ^{3} |