Sum of Consecutive Cubes

Calculate the sum of first n cubes or the sum of consecutive cubic numbers from n13 to n23 . A cube number (or a cube) is a number you can write as a product of three equal factors of natural numbers. The sum of consecutive cubic numbers from n13 to n23 is equal to:
n13 + (n1 + 1)3 + ... + n23
Enter the Nth term :
 
Sum of consecutive cubes:
let's understand the simple method to calculate the Sum of consecutive squares for given value as follows:
for example we input these value 5 it means we wants the sum of 13,23,33,43, and 53
= 1x1x1 + 2x2x2 + 3x3x3 + 4x4x4 + 5x5x5
= 1 + 8 + 27 + 64 + 125
= 225
now calculate the same example using following formula:
Sum of consecutive squares = (n2(n + 1)2/4 )
= 5x5 (5 + 1)(5 + 1)/4
= 25 (6x6)/4
= 25x36/4
= 25x9
= 225